Frank Cazabon
2018-11-09 15:27:12 UTC
Hi,
CREATE CURSOR Merchants ;
(MerchantID i,;
MerchantName c(10))
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (1, "Freddie")
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (2, "Brian")
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (3, "Roger")
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (4, "John")
CREATE CURSOR Emails;
(EmailID i,;
MerchantID i,;
Email c(30))
INSERT INTO Emails (EmailId, MerchantID, Email) VALUES (1, 2,
"***@queen.com")
INSERT INTO Emails (EmailId, MerchantID, Email) VALUES (2, 2,
"***@gmail.com")
INSERT INTO Emails (EmailId, MerchantID, Email) VALUES (3, 4,
"***@queen.com")
CREATE CURSOR Templates ;
(TemplateID i,;
TemplateName c(10))
INSERT INTO Templates (TemplateID, TemplateName) VALUES (1, "template 1")
INSERT INTO Templates (TemplateID, TemplateName) VALUES (2, "template 2")
CREATE CURSOR MerchantTemplates;
(MerchantTemplateID i,;
MerchantID i,;
TemplateID i)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (1, 2, 1)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (2, 2, 2)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (3, 4, 1)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (4, 4, 2)
I need to create a report like this (the email and template columns must
be side by side):
*Merchant**
* *Email**
* *Template*
Freddie
Brian
***@queen.com
Template 1
Brian
***@gmail.com
Template 2
Roger
John
***@queen.com
Template 1
John
Template 2
This was my attempt to build the data, but I get doubling up:
SELECT MerchantName;
,Email;
,TemplateName ;
FROM Merchants ;
LEFT JOIN Emails ON Merchants.MerchantID = Emails.MerchantID;
LEFT JOIN MerchantTemplates ON Merchants.MerchantID =
MerchantTemplates.MerchantID;
LEFT JOIN Templates ON MerchantTemplates.TemplateId =
Templates.TemplateID
Can I do this in SQL or do I need to build my cursor up procedurally?
--
Frank.
Frank Cazabon
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CREATE CURSOR Merchants ;
(MerchantID i,;
MerchantName c(10))
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (1, "Freddie")
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (2, "Brian")
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (3, "Roger")
INSERT INTO Merchants (MerchantID, MerchantName) VALUES (4, "John")
CREATE CURSOR Emails;
(EmailID i,;
MerchantID i,;
Email c(30))
INSERT INTO Emails (EmailId, MerchantID, Email) VALUES (1, 2,
"***@queen.com")
INSERT INTO Emails (EmailId, MerchantID, Email) VALUES (2, 2,
"***@gmail.com")
INSERT INTO Emails (EmailId, MerchantID, Email) VALUES (3, 4,
"***@queen.com")
CREATE CURSOR Templates ;
(TemplateID i,;
TemplateName c(10))
INSERT INTO Templates (TemplateID, TemplateName) VALUES (1, "template 1")
INSERT INTO Templates (TemplateID, TemplateName) VALUES (2, "template 2")
CREATE CURSOR MerchantTemplates;
(MerchantTemplateID i,;
MerchantID i,;
TemplateID i)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (1, 2, 1)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (2, 2, 2)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (3, 4, 1)
INSERT INTO MerchantTemplates (MerchantTemplateID, MerchantID,
templateID) VALUES (4, 4, 2)
I need to create a report like this (the email and template columns must
be side by side):
*Merchant**
* *Email**
* *Template*
Freddie
Brian
***@queen.com
Template 1
Brian
***@gmail.com
Template 2
Roger
John
***@queen.com
Template 1
John
Template 2
This was my attempt to build the data, but I get doubling up:
SELECT MerchantName;
,Email;
,TemplateName ;
FROM Merchants ;
LEFT JOIN Emails ON Merchants.MerchantID = Emails.MerchantID;
LEFT JOIN MerchantTemplates ON Merchants.MerchantID =
MerchantTemplates.MerchantID;
LEFT JOIN Templates ON MerchantTemplates.TemplateId =
Templates.TemplateID
Can I do this in SQL or do I need to build my cursor up procedurally?
--
Frank.
Frank Cazabon
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text/plain (text body -- kept)
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_______________________________________________
Post Messages to: ***@leafe.com
Subscription Maintenance: http://mail.leafe.com/mailman/listinfo/profox
OT-free version of this list: http://mail.leafe.com/mailman/listinfo/profoxtech
Searchable Archive: http://leafe.com/archives/search/profox
This message: http://leafe.com/archives/byMID/profox/e4283eeb-cf5d-5eeb-64b3-***@gmail.com
** All postings, unless explicitly stated otherwise, are the opinions of the author, and do not constitute legal or medical advice. This statement is added to the messages for those lawyers who are